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Oxides of Sulphur

The oxidation...

Question

The oxidation states of transition metal atoms in $K_{2} C r_{2} O_{7},$ $K M n O_{4}$ and $K_{2} F e O_{4},$ respectively, are $x, y a n d z .$ The sum of $x, y$ and $z$ is:

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Solution

$K_{2} C r_{2} O_{7}$
$2 (+ 1) + 2 x + 7 (- 2) = 0$
$x = + 6$

$K M n O_{4}$
$(+ 1) + y + 4 (- 2) = 0$
$y = + 7$

$K_{2} F e O_{4}$
$2 (+ 1) + z + 4 (- 2) = 0$
$z = + 6$

So, $x = 6$
$y = 7$
$z = 6$
Therefore, $x + y + z = 19$

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Oxides of Sulphur

Standard XII Chemistry

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