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Question

The oxidation states of transition metal atoms inK2Cr2O7,KMnO4andK2FeO4, respectively, are x,yandz. The sum of x,yandz is


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Solution

Step 1: Identify transitional metal in given compounds

  • The transitional metals in K2Cr2O7,KMnO4andK2FeO4 are Cr,MnandFe .

Step 2: Compute the oxidation state of transitional atoms

  • The oxidation state of Cr in K2Cr2O7 is,
  • 2+1+2x+7-2=02x=12x=+6
  • And the oxidation state of Mn in KMnO4 is,
  • +1+y+4-2=0y=+7
  • Similarly, the oxidation of Fe in K2FeO4 is,
  • 2+1+z+4-2=0z=+6

Step 3: Compute the sum of x,yandz

  • x+y+z=6+7+6=19

Hence, the sum of x,yandz is 19.


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