The oxide of a metal has 32% oxygen. Its equivalent weight would be

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Solution

The correct option is C 17
Let weight of metal oxide = 100gm
Weight of oxygen = 32gm
$∴$ weight of metal=100-32=68 gm
Equivalent weight of oxide $= \frac{w t . o f m e t a l}{w t . o f o x y g e n} \times 8 = \frac{68}{32} \times 8 = 17$

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The oxide of a metal has 32% oxygen. Its equivalent weight would be

The correct option is C 17Let weight of metal oxide = 100gm Weight of oxygen = 32gm ∴ weight of metal=100-32=68 gm Equivalent weight of oxide =wt. of metalwt. of oxygen×8=6832×8=17

The correct option is C 17
Let weight of metal oxide = 100gm
Weight of oxygen = 32gm
$∴$ weight of metal=100-32=68 gm
Equivalent weight of oxide $= \frac{w t . o f m e t a l}{w t . o f o x y g e n} \times 8 = \frac{68}{32} \times 8 = 17$