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Question
The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :
The oxide of a metal (R) can be reduced by the metal (P) and metal (R) can reduce the oxide of metal (Q). Then the decreasing order of the reactivity of metal (P), (Q) and (R) with oxygen is :
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Solution
The correct option is C P > R > Q
As R can reduce oxide of Q, so R is more reactive than Q. P can reduce oxide of R so P is more reactive than R.
So, reactivity order is P > R > Q.
As R can reduce oxide of Q, so R is more reactive than Q.
P can reduce oxide of R so P is more reactive than R.
So, reactivity order is P > R > Q.
So, reactivity order is P > R > Q.
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