The oxide that gives $H_{2} O_{2}$ on treatment with a dilute acid is :

P b O_{2}

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N a_{2} O_{2}

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M n O_{2}

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B a O_{2}

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Solution

The correct option is B $N a_{2} O_{2}$
The oxide that gives $H_{2} O_{2}$ on treatment with a dilute acid is $N a_{2} O_{2}$ . Only true peroxides which have -O-O- bond give hydrogen peroxide with dilute acids.
$N a_{2} O_{2} + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O_{2}$

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Similar questions

H_{2} O_{2}

H_{2} S O_{4}

The oxide that gives hydrogen peroxide ( $H_{2} O_{2}$ ) on the treatment with a dilute acid ( $H_{2} S O_{4}$ ) is

H_{2} O_{2}

Question 7

The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is

(a) $P b O_{2}$ (b) $B a O_{2} .8 H_{2} O + P_{2}$

(H_{2} O_{2})

(H_{2} {S O}_{4})

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