The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is:

P b O_{2}

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B a O_{2} . 8 H_{2} O

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M n O_{2}

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T i O_{2}

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Solution

The correct option is D $B a O_{2} . 8 H_{2} O$
The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is $B a O_{2} . 8 H_{2} O$ .
$B a O_{2} . 8 H_{2} O (s) + H_{2} S O_{4} (a q) \to B a S O_{4} (s) + H_{2} O_{2} (a q) + 8 H_{2} O (l)$

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Question 7

The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is

(a) $P b O_{2}$ (b) $B a O_{2} .8 H_{2} O + P_{2}$

The oxide that gives hydrogen peroxide ( $H_{2} O_{2}$ ) on the treatment with a dilute acid ( $H_{2} S O_{4}$ ) is

H_{2} O_{2}

H_{2} O_{2}

(H_{2} O_{2})

(H_{2} {S O}_{4})

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