The oxyacid of phosphorous which has more non- ionisable hydrogens :

H_{3} P O_{2}

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H_{3} P O_{3}

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H_{4} P_{2} O_{7}

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H_{4} P_{2} O_{6}

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Solution

The correct option is A $H_{3} P O_{2}$
$H_{3} P O_{2}$
more non-ionisable hydrogen

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Oxidation states of $P$ in $H_{4} P_{2} O_{6}, H_{4} P_{2} O_{6}, H_{4} P_{2} O_{7}$ are respectively:

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