The p-d- V across and current I flowing through an instrument in an a-c- circuit are given by V-2cos- t V and I-2sin - t A- The power dissipated in the instrument is-

The correct option is A 0 W Given, V=2cos #160; ω t I=2sin #160; nω t #160; ϕ #160; = 90^0 cosϕ #160; = 0 ∴ P = 0 ...

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Standard XII

Physics

Capacitor in an AC Circuit

The p.d. V ...

Question

The $p . d . V$ across and current $I$ flowing through an instrument in an $a . c .$ circuit are given by $V = 2 cos ω t V$ and $I = 2 sin ω t A$ . The power dissipated in the instrument is:

0 W

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2.5 W

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1.5 W

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9 W

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Solution

The correct option is A $0 W$
Given,
$\begin{matrix} V = 2 cos ω t I = 2 sin n ω t \end{matrix}$
$ϕ = 90^{0}$
$cos ϕ = 0$
$∴ P = 0$
$∴$ Option $A$ is correct.

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The p.d. V across and current I flowing through an instrument in an a.c. circuit are given by V=2cosω t V and I=2sin ωt A. The power dissipated in the instrument is:

The correct option is A 0 WGiven,V=2cosωtI=2sinnωtϕ=900cosϕ=0∴P=0∴ Option A is correct.

The $p . d . V$ across and current $I$ flowing through an instrument in an $a . c .$ circuit are given by $V = 2 cos ω t V$ and $I = 2 sin ω t A$ . The power dissipated in the instrument is:

The correct option is A $0 W$
Given,
$\begin{matrix} V = 2 cos ω t I = 2 sin n ω t \end{matrix}$
$ϕ = 90^{0}$
$cos ϕ = 0$
$∴ P = 0$
$∴$ Option $A$ is correct.