Question

The $P-P-P$ angle in $P_4$ molecule and $S-S-S$ angle in $S_8$ molecule is (in degree) respectively:

• A. ${60}^o,{107}^o$
• B. ${107}^o,{60}^o$
• C. ${60}^o,{108}^o$
• D. ${60}^o,{40}^o$

Answer 1

The correct option is A ${60}^o,{107}^o$

In$P_4$ molecule, the four ${Sp}^3$ hybridized phosphorous atoms lie at the corners of a regular tetrahedron with $\angle PPP={60}^o$.

In $S_8$ molecule, $S-S-S$ angle is ${107}^o$.

Hence, option A is correct.