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Question

The P-V diagram of 2 gm of helium gas for a certain process A B is shown in the figure. what is the heat given to the gas during the process A B
 


Solution

The correct option is B
Change in internal energy from A B
U=f2μRT=f2(PfVfPiVi)
=32(2P0×2V0P0×V0)=92P0V0
work done in process  A B is equal to the area covered by the graph
with volume axis i.e.,
WAB=12(P0+2P0)×(2V0V0)=32P0V0
Hence,Q=U+W=92P0V0+32P0V0=6P+0V0

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