The P−V diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process CD is (use γ=1.4):
A
200J
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B
−500J
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C
−400J
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D
400J
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Solution
The correct option is B−500J workdone for adiabatic process is WCD=nRΔT1−γ=Pfvf−Pivi1−γ=200×3−100×41−1.4 WCD=600−400−0.4=−2000.4=−500J WCD=−500J