The P-V diagram of path followed by one mole of perfect gas in a cylindrical container is shown in figure, the work done when the gas is taken from state A to state B is:
A
2P2V1[1−√V2√V1]
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B
2P1V1[1−√V1√V2 ]
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C
2P2V2[1−√V1√V2 ]
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D
2P1V2[1−√V1√V2 ]
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Solution
The correct option is B2P1V1[1−√V1√V2 ] We know that in the polytropic process PVn=C