The $p - V$ plots for two gases during adiabatic process as shown in figure plots $1$ and $2$ should correspond respectively to.

H e

and

O_{2}

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O_{2}

and

H e

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H e

and

A r

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O_{2}

and

N_{2}

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Solution

The correct option is A $O_{2}$ and $H e$
Slope of adiabatic process of p-V diagram
$(\frac{d p}{d v}) = γ \frac{p}{V}$ i.e., slope $α γ$
From graph $(s l o p e)_{2} > (s l o p e)_{2}$
$\Rightarrow γ_{2} > γ_{1}$
$γ$ for monoatomic gas (Ar, He) is greater than $γ$ for diatomic gas $(O_{2}, N_{2})$ .

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