Question

The paint in a certain container is sufficient to paint an area equal to 9.375 sq.m. How many bricks of dimensions 22.5 cm $\times$ 10 cm $\times$ 7.5 cm can be painted out of this container?

Answer 1

Given,
Dimensions of the brick = 22.5 cm $\times$ 10 cm $\times$ 7.5 cm

Here, $l=22.5cm,b=10cm,h=7.5cm$

Surface area of 1 brick $=2(lb+bh+hl)$

$=2(22.5\times 10+10\times 7.5+7.5\times 22.5)$

$=2(225+75+168.75)=2\times 468.75=937.5c{m}^2$

Area that can be painted by the container = 9.375 m${}^2$ (given)

$=9.375\times 10000=93750c{m}^2$

Thus, the required number of bricks

$=\frac{\text{(Area that can be painted by the container)}}{\text{(Surface area of 1 brick)}}=\frac{93750}{937.5}=100$