Question

The paint in a certain container is sufficient to paint an area of $9.375m^2$. How many bricks increasing $22.5cm\times 10cm\times 7.5cm$ can be painted out of his container?

Answer 1

Given,

The point in a certain container is sufficient to paint on area(a)$=9.375m^2$

also given to find out how many bricks can be painted out of the paint.

$22.5cm\times 10cm\times 7.5cm$

Let, length(L)$=22.5$cm

breadth(b)$=10$cm

height(h)$=7.5$cm

As we know that,

Total surface area of a rectangle$=2(lb+bh+hl)$ sq. units

So, we get

Total surface area of bricks

$=2[22.5\times 10+10\times 7.5+7.5\times 22.5]$

$\Rightarrow 2[225+75+168.75]$

$\Rightarrow 2\left[468.75\right]$

$\Rightarrow$ Total surface area of bricks$=937.5c{m}^2$

$\Rightarrow \frac{9375}{10}$

Now, painting an area$=9.375m^2$ [given]

$\Rightarrow 93750$cm. $(\because l=100cm,l{m}^2=1000cm2)$

$\therefore$ No. of bricks$=\frac{937500}{9375}\Rightarrow 100$ $[\because \frac{93750}{\frac{937.5}{10}}\Rightarrow \frac{937500}{9375}]$

$\therefore$ Paint is sufficient for $100$ bricks.