Question

The paint in a certaint container insuffcient to paint and area equal to $9.375m^2$. How many bricks of dimensions $22.5cm.\times 10cm\times 7.5cm$ can be painted out of this container?

Answer 1

We have,

$h=7.5cm.$

$b=10cm.$

$l=22.5cm.$

Number of bricks that can be painted out of the container$=\frac{\text{Area}\text{than}\text{can}\text{be}\text{painted}\text{by}\text{the}\text{container}}{\text{surface}\text{area}\text{of}\text{bricks}}$

Area that can be painted by the container $=9.375m^2$

$9.375m^2$

$=9.375\times {\left(100\right)}^2$

$=9.375\times 10000c{m}^2$

$=93750c{m}^2$

Total surface area of one brick$=2(lb+bh+hl)$

$=\left[2(22.5\times 10+10\times 7.5+22.5\times 7.5)\right]c{m}^2$

$=2(225+75+168.75)$

$=2\left(468.75\right)$

$=937.5c{m}^2$

So,

Number of bricks

$=\frac{93750}{937.5}$

$=\frac{937500}{9375}$

$=100$

Hence, the number of bricks$=100$

Hence, this is the answer.