Question

The pair having the same magnetic moment is :
[At. No.: Cr=24, Mn=25, Fe=26, Co=27]

• A. $\left[Cr\right(H_{2}O{)}_6{]}^{2+}and\left[Fe\right(H_{2}O{)}_6{]}^{2+}$
• B. $\left[Mn\right(H_{2}O{)}_6{]}^{2+}and\left[Cr\right(H_{2}O{)}_6{]}^{2+}$
• C. $\left[CoC{l}_4{]}^{2-}and\right[Fe(H_{2}O{)}_6{]}^{2+}$
• D. $\left[Cr\right(H_{2}O{)}_6{]}^{2+}and[CoC{l}_4{]}^{2-}$

Answer 1

The correct option is A $\left[Cr\right(H_{2}O{)}_6{]}^{2+}and\left[Fe\right(H_{2}O{)}_6{]}^{2+}$

Each $\left[Cr\right(H_{2}O{)}_6{]}^{2+}and\left[Fe\right(H_{2}O{)}_6{]}^{2+}$
Contain 4 unpaired electron.