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B
HgCl2,SnCl2
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C
FeCl2,SnCl2
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D
FeCl3,Kl
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Solution
The correct option is CFeCl2,SnCl2 The pair of compounds that can exist together is FeCl2,SnCl2. FeCl2 and SnCl2 (both are reducing agent and have lower oxidation no.) Hence neither can reduce other. The higher oxidation states includes FeCl3,SnCl4.