The correct option is B sp
A carbanion is an anion in which carbon is trivalent (forms three bonds) and bears a formal negative charge.
The negative charge of a carbanion is localized in any sp hybridised orbital on carbon depending on their availability of lone pair.
CH3−C≡C− : In the carbanion the carbon is having 1 sigma bond , 2π bonds and 1 lone pair , therefore, C is sp hybridised .
Hence, option (d) is correct.