Question

The pair of electrons in the given carbanion, $C{H}_{3}C\equiv C^{-}$, is present in which orbital?

• A. $s{p}^3$
• B. $s{p}^2$
• C. $sp$
• D. $2p$

Answer 1

The correct option is C

$sp$

$Hybridisation=\frac{Numberof\sigma -electrons}{2}=\frac{2+2\left(negativeion\right)}{2}=2=sp$

Hence, in the carbanion, $C{H}_{3}C\equiv C,$ the pair of electrons represent as the negative charge is present in sp-hybridised-orbital.