The pair of elements forming ionic bond is :

C l + C l \to C l_{2}

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H + F \to H F

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N a + B r \to N a B r

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O + H \to H_{2} O

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Solution

The correct option is D $N a + B r \to N a B r$
Sodium's Ionization Potential is less, Br electron affinity is more. The type of bond is formed is ionic bond.

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Similar questions

Q. Increasing order of ionic character in followoing bonds is

C - H < B r - H < N a - I < F - H < L i - C l < K - F

If true enter 1, else enter 0.

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

Q. The correct order of increasing

X - O - X

bond angle is

(X = H, F or C l)

Q. The correct order of decreasing

X - O - X

bond angle is:

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The pair of elements forming ionic bond is :

The correct option is D Na+Br→NaBrSodium's Ionization Potential is less, Br electron affinity is more. The type of bond is formed is ionic bond.

The correct option is D $N a + B r \to N a B r$
Sodium's Ionization Potential is less, Br electron affinity is more. The type of bond is formed is ionic bond.