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Question

The pair of equations 2x+3y=5 and 4x+6y=15 has

(a) a unique solution (b) exactly two solution

(c) infinitely many solutions (d) no solution

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Solution

Given system of equations is: 2x + 3y = 5 and 4x + 6y = 10.

They can be rewritten as:

2x + 3y - 5 = 0 and

4x + 6y - 10 = 0

Herea subscript 1 over a subscript 2 equals b subscript 1 over b subscript 2 equals c subscript 1 over c subscript 2

ie 2 over 4 equals 3 over 6 equals fraction numerator negative 5 over denominator negative 10 end fraction

or 1 half equals 1 half equals 1 half

So, the given system of equations is consistent and possess infinitely many solutions.

So option c is correct.


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