The pair of given lines x+2y−4=0 and 2x+4y−12=0 are ____
Since, condition for parallel lines: a1a2=b1b2≠c1c2 Given: x+2y−4=0 and 2x+4y−12=0
Here 12=24≠−4−12
Hence, the lines are parallel.
How many solutions are possible for the following pair of equation? 2 x + 4 y -12= 0 and x + 2y- 4 =0