The pair of lines and $2 x - 7 y - 5 = 0$ are consistent.

x = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $x = 2$
For a pair of lines to be consistent, either $\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}} o r \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$ .
In x = 2; 2x - 7y - 5 = 0,
$\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}} .$
In all the other options,
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}} .$
Therefore, the equations $x = 2$ and $2 x - 7 y - 5 = 0$ are consistent.

Suggest Corrections

Similar questions

2 x - 7 y - 5 = 0

x + y - 1 = 0, (m - 1) x + (m^{2} - 7) y - 5 = 0

(m - 2) x + (2 m - 5) y = 0

x + y = 1,

(k - 1) x + (k^{2} - 7) y - 5 = 0

(k - 2) x + (2 k - 5) y = 0

2 x + 5 y - 3 = 0 k x + 7 y + 5 = 0

2 x - 2 y - 2 = 0, 4 x - 4 y - 5 = 0

Join BYJU'S Learning Program