The pair of lines represented by 3ax2+5xy+a2-2y2=0 are perpendicular to each other for
Two values of a
For all a
For one value of a
For no value of a
Explanation for the correct option
Given, 3ax2+5xy+a2-2y2=0
The condition for the lines to be perpendicular is
coefficientofx2+coefficientofy2=0⇒3a+a2-2=0∴a=-3±32-4×1×-22a=-3±172
So, we get two values of a.
Hence, option A is the correct answer.