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Magnetic Moment Examples

The pair of m...

Question

The pair of metal ions that can give a spin only magnetic moment of $3.9 B M$ for the complex $[M (H_{2} O)_{6}] C l_{2}$ , is:

C r^{2 +}

and

M n^{2 +}

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V^{2 +}

and

C o^{2 +}

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V^{2 +}

and

F e^{2 +}

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C o^{2 +}

and

F e^{2 +}

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Solution

The correct option is A $V^{2 +}$ and $C o^{2 +}$
Spin only magnetic moment given as $μ = \sqrt{n (n + 2)}$

where $n =$ number of unpaired electron

$μ = \sqrt{n (n + 2)} = 3.9 \Rightarrow n \approx 3$

So, there are $3$ unpaired $e^{-}$ which is possible only in the compounds shown in the figure, $V^{+ 2} a n d C o^{+ 2}$ .

Others won't have 3 unpaired electrons-
$C r^{+ 2} \Rightarrow 3 d^{4} \Rightarrow 4 u n p a i r e d e l e c t r o n s$
$M n^{+ 2} \Rightarrow 3 d^{5} \Rightarrow 5 u n p a i r e d e l e c t r o n s$
$F e^{+ 2} \Rightarrow 3 d^{6} \Rightarrow 4 u n p a i r e d e l e c t r o n s$

Hence, the correct is B.

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Similar questions

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

F e^{2 +}

T i^{2 +}

C u^{2 +}

V^{2 +}

F e^{2 +}

T i^{2 +}

C u^{2 +}

V^{2 +}

F e^{2 +}

V^{2 +} < C r^{2 +} < M n^{2} < F e^{2 +}

N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

C o^{3 +} < F e^{3 +} < C r^{3 +} < S c^{3 +}

S c < T i < C r < M n

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