The pair of metals which displace hydrogen from the caustic soda solution is :

N a, A l

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M g, Z n

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A l, Z n

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N a, M g

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Solution

The correct options are
A $N a, A l$
C $A l, Z n$
$N a + N a O H ⟶ N a_{2} O + H_{2}$ $- (I)$
$A l + N a O H ⟶ N a A l O_{2} + H_{2} + N a_{2} O$ $- (I I)$
$M g + N a O H ⟶ M g (O H)_{2} + N a$ $- (I I I)$
$Z n + N a O H ⟶ N a_{2} Z n O_{2} + H_{2}$ $- (I V)$
From the above four reactions it is clear that $M g$ does not displace hydrogen from $N a O H$ (i.e. caustic soda). Therefore, (A) and (C) are the correct options.

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The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
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Question 17
Arrange the following elements in the order of their decreasing metallic character
Na, Si, Cl, Mg, Al

(a) Cl > Si >Al > Mg >Na
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A l, C u, F e, M g

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E_{A l^{3} + / A l}^{0} + - 1.66 V, E_{C u^{2} + / C u}^{0} = + 0.34 V

E_{F e^{2} + / F e}^{0} = - 0.44 V, E_{M g^{2} + / M g}^{0} = - 1.40 V

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