Question

The pair of species having identical shapes for molecules of both species is:

• A. $C{F}_4,S{F}_4$
• B. $Xe{F}_2,C{O}_2$
• C. $B{F}_3,PC{l}_3$
• D. $P{F}_5,I{F}_5$

Answer 1

The correct option is B $Xe{F}_2,C{O}_2$

(a)
$C{F}_4$ is tetrahedral in shape, hybridisation $s{p}^3$ and $S{F}_4$ is $s{p}^{3}d$ hybridised and Sea saw in shape.
(b)
Central atom in $C{O}_2$ is $sp$ hybridised shows linear shape and $Xe$ in $Xe{F}_2$ is $s{p}^{3}d$ hybridised and is linear in shape.
$F-Xe-F$ $O=C=O$
(c) $B{F}_3$ is $s{p}^2$ hybridised aqnd trigonal planar in shape whereas $PC{l}_3$ is $s{p}^3$ hybridised and trigonal pyramidal in shape.
(d) $PC{l}_5$ is $s{p}^{3}d$ hybridised and trigonal bipyramidal in shape whereas $I{F}_5$ is $s{p}^3{d}^2$ hybridised and square pyramidal in shape
Hence, option (b) is correct.