The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is(are):

[C r (N H_{3})_{5} C l] C l_{2}

and

[C r (N H_{3})_{4} C l_{2}] C l

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[C o (N H_{3})_{4} C l_{2}]^{+}

and

[P t (N H_{3})_{2} (H_{2} O) C l]^{+}

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[C o B r_{2} C l_{2}]^{2 -}

and

[P t B r_{2} C l_{2}]^{2 -}

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[P t (N H_{3})_{3} (N O_{3})] C l

and

[P t (N H_{3})_{3} C l] B r

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Solution

The correct options are
B $[C o (N H_{3})_{4} C l_{2}]^{+}$ and $[P t (N H_{3})_{2} (H_{2} O) C l]^{+}$
D $[P t (N H_{3})_{3} (N O_{3})] C l$ and $[P t (N H_{3})_{3} C l] B r$
The pairs of coordination complexes/ions exhibiting the same kind of isomerism are: Octahedral $[C o (N H_{3})_{4} C l_{2}]^{+}$ and square planar $[P t (N H_{3})_{2} (H_{2} O) C l]^{+}$ which shows geometrical (cis-trans) isomerism.

Square planar $[P t (N H_{3})_{3} (N O_{3})] C l$ and square planar $[P t (N H_{3})_{3} C l] B r$ shows ionization isomerism.

The pairs of coordination complexes/ions NOT exhibiting the same kind of isomerism are:
$[C r (N H_{3})_{5} C l] C l_{2}$ neither shows structural nor stereoisomerism.

$[C r (N H_{3})_{4} C l_{2}] C l$ shows geometrical (cis trans) isomerism.

Tetrahedral $[C o B r_{2} C l_{2}]^{2 -}$ and square planar $[P t B r_{2} C l_{2}]^{2 -}$ do not show same type of isomerism.

Hence, options $B$ and $D$ are correct.

Suggest Corrections

Similar questions

[C r (N H_{3})_{5} B r] C l

[C r (N H_{3})_{5} C l] B r

[C o (N H_{3})_{4} C l_{2}] N O_{2}

[C o (N H_{3})_{4} C l N O_{2}] C l

[C o (N H_{3})_{4} (H_{2} O)_{2}] C l_{2}, [N i (H_{2} O)_{6}] C l_{2}, [C o (H_{2} O)_{5} C l] C l, [P t (N H_{3})_{2} C l_{2}], [P t (e n) C l_{2}], [P t (e n)_{2} C l_{2}], [P b C l_{2} B r I], [C o (N H_{3}) 4 C l_{2}], [C o (e n)_{2} B r_{2}]

_{3}

_{4}

_{2}

[C o (N H_{3})_{4} B r_{2}] C l

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