wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The pairs of linear equations which have the unique solution x=2,y=3 are,


A

x+y= 1;2x+3y= 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

2x+5y= 11;4x+10y= 22

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

2xy=1;3x+2y=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x4y14=0;5xy13=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A

x+y= 1;2x+3y= 5


D

x4y14=0;5xy13=0


Option A:

x+y= 1(i)

2x+3y= 5(ii)

(i)×2 2x+2y=2(iii)

Solving by elimination((iii)(ii)) we get,

x=2 and y=3.

Option D:

x4y=14(i)

5xy=13(ii)
(ii)×420x4y=52(iii)

Solving by elimination method ((iii)(i)) we get,

x=2 and y=3


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving simultaneous linear equation using method of elimination.
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon