Question

The parabola having its focus at $(3,2)$ and directrix along the $y$-axis has its vertex at

• A. $(2,2)$
• B. $(\frac{3}{2},2)$
• C. $(\frac{1}{2},2)$
• D. $(\frac{2}{3},2)$

Answer 1

Answer: (B)

$(\frac{3}{2},2)$

Vertex of the parabola is a point which lies on the axis of the parabola, which is a line $\perp$ to the directrix through the focus, i.e., $y=2$ and equidistant from the focus and directrix $x=0$.

So, that the vertex is $(\frac{3}{2},2)$.