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Question

The parabola y2=px passes through the point of intersection of the lines x3+y2=1 and x2+y3=1. Its focus is

A
(310,0)
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B
(35,0)
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C
(37,0)
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D
(67,0)
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Solution

The correct option is A (310,0)
Given parabola is y2=px ..... (i)
x3+y2=1 ..... (ii)
x2+y3=1 ..... (iii)
Solving above equations, we get
x=65,y=65
From (i), we get
(65)2=p×(65)
p=65
Again, from (i)
4a=65
a=310
Focus =(a,0) =(310,0)

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