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Question

The parallel rays of white light are made an incident normally on an air film of uniform thickness. 250 fringes are seen in the transmitted light between 4000Ao and 6500Ao. Thickness of air film is

A
1.3mm
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B
1.5mm
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C
0.13mm
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D
0.11mm
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Solution

The correct option is A 1.3mm
For a fringe to appear, the two wavelengths must interfere to give a maxima, which appears at a distance where the phase of both the rays are same, that is, at the least count multiple of the waves.
Therefore the first fringe appears at 5200Ao.
To accommodate 250 fringes, the thickness of the film is 250 times the distance where the first fringe occurs.
Thus the thickness of the air film is 1.3mm

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