The parallel sides of a trapezium are 25 cm and 13 cm.Its non parallel sides are 10cm each.Find the area of trapezium.

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Solution

$A = A (I) + A (I I) + A (I I I)$
$= \frac{1}{2} \times 6 \times 8 + 8 \times 13 + \frac{1}{2} \times 6 \times 8$
$= 24 + 104 + 24$
$= 152$ sq units.

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The parallel sides of a trapezium are 25 cm and 13 cm.Its non parallel sides are 10cm each.Find the area of trapezium.

A=A(I)+A(II)+A(III) =12×6×8+8×13+12×6×8 =24+104+24 =152 sq units.

$A = A (I) + A (I I) + A (I I I)$
$= \frac{1}{2} \times 6 \times 8 + 8 \times 13 + \frac{1}{2} \times 6 \times 8$
$= 24 + 104 + 24$
$= 152$ sq units.