Question

The parallel sides of a trapezium are 28 cm and 21 cm and each of the non-parallel sides is 17 cm. Find the area of the trapezium.

Answer 1

In triangle ACE-

By pythagoras theorem

$A{E}^2=A{C}^2+C{E}^2$

$A{E}^2=289-12.25$

$AE=16.67cm$

Therefore height$=16.67cm$

Hence area of the trapezium $=\frac{1}{2}\times sumofparallelsides\times height$

$=\frac{1}{2}\times 49\times 16.67$

$=408.415c{m}^2$