The parallel sides of a trapezium are $60 c m$ and $77 c m$ and other sides are $25 c m$ and $26 c m$ . Its area is

1644 c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1444 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1244 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1000 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1644 c m^{2}$
$h^{2} = 25^{2} - x^{2} = 26^{2} - (17 - x)^{2}$
$17 (17 - 2 x) = 51$
$17 - 2 x = 3$
$2 x = 14$
$x = 7$

$∴ h = 24$
Area $= \frac{1}{2} (a + b) h = \frac{1}{2} \times (60 + 77)$
$= 137 \times 12$
$= 1644 c m^{2}$

Suggest Corrections

Similar questions

The area of a trapezium is 1586 cm²and the distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm, then find the other parallel side.

Q. Find the height of a trapezium in which parallel sides are 25 cm and 77 cm and non-parallel sides and 26 cm and 60 cm.Given the area of the trapezium as

1644 c m^{2}

Q. The parallel sides of a trapezium are 25 cm and 11 cm, while its nonparallel sides are 15 cm and 13 cm. Find the area of the trapezium.

A field is in the shape of a trapezium whose parallel sides are $25cm and 10cm$ . If its non-parallel sides are $14cm and 13cm$ . Find its area ___ (in $c m^{2}$ ).

Join BYJU'S Learning Program

The parallel sides of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Its area is

The correct option is A 1644 cm2h2=252−x2=262−(17−x)217(17−2x)=5117−2x=32x=14 x=7∴h=24Area =12(a+b)h=12×(60+77)=137×12=1644 cm2

The parallel sides of a trapezium are $60 c m$ and $77 c m$ and other sides are $25 c m$ and $26 c m$ . Its area is

The correct option is A $1644 c m^{2}$
$h^{2} = 25^{2} - x^{2} = 26^{2} - (17 - x)^{2}$
$17 (17 - 2 x) = 51$
$17 - 2 x = 3$
$2 x = 14$
$x = 7$

$∴ h = 24$
Area $= \frac{1}{2} (a + b) h = \frac{1}{2} \times (60 + 77)$
$= 137 \times 12$
$= 1644 c m^{2}$