Question

The parallel sides of an isosceles trapezium are 25 cm and 11 cm, and the perpendicular distance between the parallel sides is 13 cm. Find the area of the trapezium.

• A. Data insufficient
• B. $234c{m}^2$
• C. $150c{m}^2$
• D. $180c{m}^2$

Answer 1

The correct option is B

$234c{m}^2$

When $h$ is the perpendicular distance between the parallel sides and the parallel sides are of length $a$ and $b$.

Area of trapezium $=h\times$ $\frac{(a+b)}{2}$sq. units

Here, $a=25cm$, $b=11cm$ and $h=13cm$

Area of Trapezium$=\frac{1}{2}\times (25+11)\times 13=234c{m}^2$