The parallel sides of trapezium are $9 c m$ and $7 c m$ long and the distance between them is $6 c m$ . Find the area of the trapezium

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Solution

Area of trapezium $= \frac{1}{2} (s u m o f p a r r a l l e l s i d e s) \times h$

$= \frac{1}{2} (9 + 7) \times 6 = 48 {c m}^{2}$

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Q. If the lengths of parallel sides of trapezium are

8 c m, 9 c m

and the distance between the parallel sides is

6 c m

, then its area is

Find the area of trapezium $A B C D$ whose parallel sides are $A B = 19 c m$ , $D C = 9 c m$ , and non parallel sides are $B C = 8 c m$ and $D A = 6 c m$ .

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The parallel sides of trapezium are 9cm and 7cm long and the distance between them is 6cm. Find the area of the trapezium

Area of trapezium =12(sumofparrallelsides)×h =12(9+7)×6=48cm2

The parallel sides of trapezium are $9 c m$ and $7 c m$ long and the distance between them is $6 c m$ . Find the area of the trapezium

Area of trapezium $= \frac{1}{2} (s u m o f p a r r a l l e l s i d e s) \times h$

$= \frac{1}{2} (9 + 7) \times 6 = 48 {c m}^{2}$