The parametric coordinates of any point on the circle x2+y2−4x−4y=0 are-
A
(−2+2cosα,−2+2sinα)
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B
(2+2cosα,2+2sinα)
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C
(2+2√2cosα,2+2√2sinα)
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D
(−2+2√2cosα,−2+2√2sinα)
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Solution
The correct option is C(2+2√2cosα,2+2√2sinα) x2+y2−4x−4y=0 ⇒(x−2)2+(y−2)2=(2√2)2 Hence any parametric point on the circle is given by, (2+2√2cosα,2+2√2sinα)