The parametric equation of a circle is given by x-3cos- -2- y-3sin- Then its

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Range of Trigonometric Expressions

The parametri...

Question

The parametric equation of a circle is given by $x = 3 cos ϕ + 2$ , $y = 3 sin ϕ$ . Then its

centre

= (- 2, 0)

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radius

= 3

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centre

= (2, 0)

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radius

= 1

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Solution

The correct options are
B centre $= (2, 0)$
C radius $= 3$
Given parametric equations of circle
$x = 3 cos ϕ + 2$ , $y = 3 sin ϕ$
Comparing with standard parametric equations of circle
$x = h + r cos t$ , $y = k + r sin t$
So, here center $(h, k) = (2, 0)$ and $r = 3$

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The parametric equation of a circle is given by x=3cosϕ+2, y=3sinϕ. Then its

The correct options are B centre =(2,0) C radius =3Given parametric equations of circle x=3cosϕ+2, y=3sinϕComparing with standard parametric equations of circle x=h+rcost , y=k+rsintSo, here center (h,k)=(2,0) and r=3

The parametric equation of a circle is given by $x = 3 cos ϕ + 2$ , $y = 3 sin ϕ$ . Then its

The correct options are
B centre $= (2, 0)$
C radius $= 3$
Given parametric equations of circle
$x = 3 cos ϕ + 2$ , $y = 3 sin ϕ$
Comparing with standard parametric equations of circle
$x = h + r cos t$ , $y = k + r sin t$
So, here center $(h, k) = (2, 0)$ and $r = 3$