The correct option is C x=4+3t2,y=2+6t
Given: Equation of parabola (y−2)2=12(x−4)
On comparing with standard form (y−k)2=4a(x−h)
⇒a=3,h=4,k=2
Parametric equation of (y−k)2=4a(x−h) are given by
x−h=at2,y−k=2at
Hence the parametric equations for (y−2)2=12(x−4) are given by
x−4=3t2,y−2=6t
⇒x=4+3t2 , y=2+6t