CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The parametric equations of the circle 4x2+4y2=25 is

A
x=52cosθ,y=32sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=52cosθ,y=52sinθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x=72cosθ,y=72sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=12cosθ,y=12sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B x=52cosθ,y=52sinθ
x2+y2=254=(52)2
So, r=52
Parametric equation will be,
x=rcosθ, y=rsinθ
x=52cosθ, y=52sinθ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Piecewise Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon