The parametric point (3+t2,3t−2) represents a parabola with
A
focus at (−3,−2)
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B
vertex at (3,−2)
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C
directrix x=−5
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D
all of these
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Solution
The correct option is B vertex at (3,−2) We have, x=3+t2 and y=3t−2 ⇒x−3=t2andy+2=3t⇒(y+2)2=9(x−3)
which is a parabola with vertex at (3,−2), focus at (214,−2) and directrix x=34