The parametric representation of a parabola is x=3+t2 , y=2t-1. Its focus is at
It is given that
x = t^2+3 ...(1)
y = 2t - 1 ...(2)
From (1)
t^2= x-3
and (2),
t^2=(y+1)^2/4
we get
(y +1)^2 = 4 (x –3) ...(3)
Let Y = y +1 and X = x – 3
Then
(3) ⇒ Y2 = 4X
Equation of the directrix for parabola Y2 = 4X is:
X = –1
⇒ x – 3 = –1
⇒ x = 3-1=2
This is the required equation of directirx.