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Question

The partial differential equation that can be formed from z=ax+by+ab has the form (withp=zxandq=zy)

A
z=px+qy
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B
z=px+pq
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C
z=px+qy+pq
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D
z=qy+pq
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Solution

The correct option is C z=px+qy+pq
Given, z=ax+by+ab ... (i)
Differentiating the above eqation partially w.r.t x & y, separately, we get
zx=a=p (say) .... (ii)
zy=b=q (say) .... (iii)
z=px+qy+pq; the required differential equation

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