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Raoult's Law

The partial p...

Question

The partial pressure of hydrogen in a flask containing two grams of hydrogen and 32 gm of sulphur dioxide is :

\frac{1}{16}

of the total pressure

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\frac{1}{9}

th of the total pressure

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\frac{2}{3}

rd of the total pressure

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\frac{1}{8}

th of the total pressure

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Solution

The correct option is C $\frac{2}{3}$ rd of the total pressure
$P = P_{H_{2}} + P_{S O_{2}}$

$P = (n_{H_{2}} + n_{S O_{2}} / V) R T = (2 / 2 + 32 / 64) / V) R T = 1.5 / V R T$

$P_{H_{2}} = (1 / V) R T$

$\frac{P_{H_{2}}}{P} = \frac{1}{1.5} \Rightarrow P_{H_{2}} = 2 / 3 P$

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