Question

The partial pressure of three gases A, B and C enclosed in a container are in the ratio 1 : 2 : 3. If the molecular weights of A, B and C are in the ratio 6 : 3 : 2, then the ratio by weights they are taken in the container is –

• A. 1 : 1 : 1
• B. 1 : 3 : 9
• C. 1 : 4 : 9
• D. 36 : 9 : 4

Answer 1

The correct option is A 1 : 1 : 1

We know that $P\propto n\Rightarrow n\propto p$

$\Rightarrow$ Ratio of moles of A : B : C = 1 : 2 : 3
and Ratio of molecular wt. of A, B, C = 6 : 3 : 2
$\Rightarrow$ Ratio of wt. of A, B $\&$ C = $1\times 6:2\times 3:3\times 2$
= 6 : 6 : 6
= 1 : 1 : 1