The particle displacement in a wave is given by y-0-2- 10 -5 cos 500t-0-025x Where the distances are measured in meters and time in seconds- Now

The correct options are A Wave velocity is 2 × 10^4 ms^ 1 C Initial phase difference is π 2 D Wavelength of the wave is (80π) m ...

You visited us 5 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Gamma Rays

The particle ...

Question

The particle displacement in a wave is given by
$y = 0.2 \times 10^{- 5} cos (500 t - 0.025 x)$
Where the distances are measured in meters and time in seconds. Now

Wave velocity is

2 \times 10^{4} {m s}^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Particle velocity is

2 \times 10^{4} {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Initial phase difference is

\frac{π}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Wavelength of the wave is

(80 π) m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A Wave velocity is $2 \times 10^{4} {m s}^{- 1}$
C Initial phase difference is $\frac{π}{2}$
D Wavelength of the wave is $(80 π) m$

Suggest Corrections

Similar questions

Q. The equation of a simple harmonic wave is given by

y = 3 sin \frac{π}{2} (50 t - x)

where

x

and

y

are in meters and

t

is in seconds. The ratio of maximum particle velocity to the wave velocity is:

Q. The equation of a progressive wave is

y = 0.05 sin (200 t - \frac{x}{2})

where

x, y

are in metres and

t

in seconds, then

a ) velocity of wave is

100 m s^{- 1}

b) maximum velocity of particle in the wave is

10 m s^{- 1}

c) wavelength of wave is

4 π m

Q. The displacement equation of a travelling sound wave along

x

axis is given by

s = 5 \times 10^{- 5} sin (500 t - 2 x)

, where

s

and

x

are in meters and

t

in seconds. Choose the correct option(s) among the following.

Q. The equation of a travelling sound wave along

x - a x i s

is given as

S = 9 sin (400 t - 2.7 x)

, where

S

is measured in

10^{- 4} m

t

in seconds and

x

in metres. Then:

Q. The displacement of a particle of the medium due to a wave moving in the positive

x -

direction is given by

y = \frac{1}{(1 + x^{2})}

at time

t = 0

and by

y = \frac{1}{1 + {(x - 1)}^{2}}

t = 2

second, where

x

and

y

are in metre. The velocity of the wave in

m/s

Join BYJU'S Learning Program

The particle displacement in a wave is given by y=0.2×10−5cos(500t−0.025x)Where the distances are measured in meters and time in seconds. Now

The correct options are A Wave velocity is 2×104 ms−1 C Initial phase difference is π2 D Wavelength of the wave is (80π) m

The particle displacement in a wave is given by
$y = 0.2 \times 10^{- 5} cos (500 t - 0.025 x)$
Where the distances are measured in meters and time in seconds. Now

The correct options are
A Wave velocity is $2 \times 10^{4} {m s}^{- 1}$
C Initial phase difference is $\frac{π}{2}$
D Wavelength of the wave is $(80 π) m$