The particle executing simple harmonic motion has a kinetic energy K0cos2ωt. The maximum values of the potential energy and the total energy are respectively:-
A
K0and K0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0and2K0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
K02andK0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
K0and2K0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is AK0and K0 ∵K.E=K0cos2ωt ∴MaximumP.E.=MaximumK.E. =Totalenergy=K0