The particle executing simple harmonic motionhas a kinetic energy K0cos2- t- The maximumvalues of the potential energy and the totalenergy are respectively-

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The particle ...

Question

The particle executing simple harmonic motion
has a kinetic energy $K_{0} c o s^{2} ω t .$ The maximum
values of the potential energy and the total
energy are respectively:-

K_{0}

and

K_{0}

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0 a n d 2 K_{0}

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\frac{K_{0}}{2} a n d K_{0}

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K_{0} a n d 2 K_{0}

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Solution

The correct option is A $K_{0}$ and $K_{0}$
$∵ K . E = K_{0} c o s^{2} ω t$
$∴ M a x i m u m P . E . = M a x i m u m K . E .$
$= T o t a l e n e r g y = K_{0}$

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The particle executing simple harmonic motionhas a kinetic energy K0cos2ωt. The maximumvalues of the potential energy and the totalenergy are respectively:-

The correct option is A K0and K0∵K.E=K0cos2ωt∴MaximumP.E.=MaximumK.E.=Total energy=K0

The particle executing simple harmonic motion
has a kinetic energy $K_{0} c o s^{2} ω t .$ The maximum
values of the potential energy and the total
energy are respectively:-

The correct option is A $K_{0}$ and $K_{0}$
$∵ K . E = K_{0} c o s^{2} ω t$
$∴ M a x i m u m P . E . = M a x i m u m K . E .$
$= T o t a l e n e r g y = K_{0}$